<?php

return <<<'SQL'
CREATE TABLE survey_question_options (
    id CHAR(36) NOT NULL PRIMARY KEY,
    question_id CHAR(36) NOT NULL,
    option_label VARCHAR(255) NOT NULL,
    sort_order INT NOT NULL DEFAULT 0,
    created_at DATETIME NOT NULL,
    updated_at DATETIME NOT NULL,
    FOREIGN KEY (question_id) REFERENCES survey_questions(id)
);
SQL;
